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命令如此
man awk > 1
用vi查看
本来用 man awk查看的时候显示的是这样
NAME
awk - pattern scanning and processing language
SYNOPSIS
awk [-F ERE][-v assignment] ... program [argument ...]
awk [-F ERE] -f progfile ... [-v assignment] ...[argument ...]
但是输出后, vi 1 成了这样:
^[[1mNAME^[[0m
awk - pattern scanning and processing language
^[[1mSYNOPSIS^[[0m
^[[1mawk [-F ^[[4m^[[22mERE^[[24m^[[1m][-v ^[[4m^[[22massignment^[[24m^[[1m] ... ^[[4m^[[22mprogram^[[24m ^[[1m[^[[4m^[[22margument^[[24m ^[[1m...]^[[0m
^[[1mawk [-F ^[[4m^[[22mERE^[[24m^[[1m] -f ^[[4m^[[22mprogfile^[[24m ^[[1m... [-v ^[[4m^[[22massignment^[[24m^[[1m] ...[^[[4m^[[22margument^[[24m ^[[1m...]^[[0m
我又用了 man awk | col -b > 1
vi 1查看是:
1mNAME0m
awk - pattern scanning and processing language
1mSYNOPSIS0m
1mawk [-F 4m22mERE24m1m][-v 4m22massignment24m1m] ... 4m22mprogram24m 1m[
4m22margument24m 1m...]0m
1mawk [-F 4m22mERE24m1m] -f 4m22mprogfile24m 1m... [-v 4m22massignment24
m1m] ...[4m22margument24m 1m...]0m
这些字符到底是什么呢?
我不知道是什么问题,望高手们给个答案. |
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