字符串匹配

linux_now

vim正则表达式如何匹配下面字符串
b-c) The char of b is b in bc, bc have two chars.
的
b-c) The char of b is b

yongjian

echo "b-c) The char of b is b in bc, bc have two chars." | sed 's/^\(.*\) in.*$/\1/g'

linux_now

如果文本的内容是这样呢？在vim中该如何用正则表达式表示开头到最后一个不是bc的b：

1. 
   
2. b-a) The char of b is b of bee bc, bc have two chars.
   
3. b-b) The char of b is before bc, bc have two chars.
   
4. b-c) The char of b is b in bc, bc have two chars.
   
5. ...
   

复制代码

要求处理后的结果：

1. 
   
2. b-a) The char of b is b of b
   
3. b-b) The char of b is b
   
4. b-c) The char of b is b

复制代码

yongjian

Post by linux_now
如果文本的内容是这样呢？在vim中该如何用正则表达式表示开头到最后一个不是bc的b：

1. 
   
2. b-a) The char of b is b of bee bc, bc have two chars.
   
3. b-b) The char of b is before bc, bc have two chars.
   
4. b-c) The char of b is b in bc, bc have two chars.
   
5. ...
   

复制代码

要求处理后的结果：

1. 
   
2. b-a) The char of b is b of b
   
3. b-b) The char of b is b
   
4. b-c) The char of b is b

复制代码

[PHP]
%s/^\(.*b\)[^b]*bc,.*$/\1/g
[/PHP]
你这样的匹配有什么实际意义吗？还是练习regexp？

猫搂鱼睡觉

sed 's/in.*\.$//g' file

zhy2111314

Post by 猫搂鱼睡觉
sed 's/in.*\.$//g' file

:ask  :ask  :ask

猫搂鱼睡觉

Post by zhy2111314
:ask  :ask  :ask

有问题吗 ?

我这边都一切OK的阿 ``
//bash

[shell]$ cat z
b-c) The char of b is b in bc, bc have two chars.
[shell]$ sed 's/in.*\.$//g' z
b-c) The char of b is b

linux_now

Post by yongjian
[PHP]
%s/^\(.*b\)[^b]*bc,.*$/\1/g
[/PHP]
你这样的匹配有什么实际意义吗？还是练习regexp？

对，练习regexp

zhy2111314

Post by 猫搂鱼睡觉
有问题吗 ?

我这边都一切OK的阿 ``
//bash

[shell]$ cat z
b-c) The char of b is b in bc, bc have two chars.
[shell]$ sed 's/in.*\.$//g' z
b-c) The char of b is b

晕，上午不行，下午可以了，好像是我看错了：（不好意思！
:p

DSL

yun!