下面的需求怎么实现 谢谢

timber_lydia

文本格式
1 3 5 7
a b c d

变成:
1  a
3  b
5  c
7  d

就是实现横排变垂着排

jayson2004

有个笨点的办法:
先定义每个元素,作个循环读取数据并赋值
A11=`cat 1.txt |sed -n '1p' | awk -F" " '{print $1}'`
A12=`cat 1.txt |sed -n '1p' | awk -F" " '{print $2}'`
...
A21=`cat 1.txt |sed -n '2p' | awk -F" " '{print $1}'`
A22=`cat 1.txt |sed -n '2p' | awk -F" " '{print $2}'`

然后作个循环写文件
echo "$A11 $A21" >2.txt
echo "$A12 $A22" >>2.txt
...

或用数组也行

chauney

awk '
        { for(i=1;i<=NF;i++) a[i,NR]=$i;}
        END
             {for(i=1;i<=NF;i++) {
                   for(j=1;j<=NR;j++) {
                            printf("%s",a[i,j]);
                            if(j==NR) print "";
                   }
              }
          }' data

bbbush

费劲死了

1. lineno=$1
   
2. for i in `seq $lineno`; do
   
3.         read strings[$i]
   
4. done
   
5. line1=(${strings[1]})
   
6. count=$((${#line1[@]} - 1))
   
7. for i in `seq 0 $count`; do
   
8.         for j in `seq $lineno`; do
   
9.                 line=(${strings[$j]})
   
10.                 echo -n "${line[$i]} "
    
11.         done
    
12.         echo
    
13. done
    

复制代码

怎么改好？

zimmerman

等待解答<hr>

richardxxg

shell code:

itpos:/home/richard/shellcode# cat ch.txt
1 3 5 7
a b c d

itpos:/home/richard/shellcode# cat foo.sh
#!/bin/sh
a=(`cat ch.txt |sed 2d |tr -d "\n"`)
b=(`cat ch.txt |sed 1d |tr -d "\n"`)
for ((i=0; i<=3;i++))
do
echo "${a[$i]} ${b[$i]}"
done

itpos:/home/richard/shellcode# sh foo.sh
1 a
3 b
5 c
7 d
itpos:/home/richard/shellcode#

richardxxg

perl code:

itpos:/home/richard/shellcode# cat ch.txt
1 3 5 7
a b c d
itpos:/home/richard/shellcode# cat foo.pl
#!/usr/bin/perl
$a=`cat ch.txt |sed 2d`;
chomp $a;
$b=`cat ch.txt |sed 1d`;
chomp $b;
@aa=split(/ /,$a);
@bb=split(/ /,$b);

for ($i=0; $i<=3;) {
      print "$aa[$i]  $bb[$i]\n";
$i++;
}
itpos:/home/richard/shellcode# perl foo.pl
1  a
3  b
5  c
7  d