該怎麼取得完整的檔名變數(已解決)

jiuny0209

假如我要對./底下所有的檔案做一個任務,可是我的檔名有" "空字符,用for會誤判為下個變數,我該怎麼取得完整的檔名呢? for i in $(ls);do echo $i;done A\ Bridge-Clannad.flac adagio\ in\ c\ minor-yanni.mp3 Almost\ a\ Whisper-yanni.mp3 A\ Lover's\ Tale-Scotland\ the\ Brave.mp3 Angels\ calling\ me-Denean.mp3 Angels\ Fall\ First-Nightwish.mp3 Angel-Shaggy.mp3 A\ Perfect\ Indian-Sinead\ O’cornor.mp3 beat\ of\ your\ heart-hayley.mp3 Butterfly\ Dance-yanni.mp3 Careless\ Whispers-George\ Michael.mp3 Childhood\ remembered-Kevin\ ..................................底下省略...........

wawxdyy

给ls加了参数,然后用cut或awk取文件名那个字段就可以了

davi

find . -maxdepth 1 -type f -print0|xargs -0 your command

jiuny0209

我只會一點點的sed,可以大概教一下sed該怎麼做嗎?提示一下就可以了....

springwind426

for i in * ; do echo "$i" ; done

jiuny0209

find . -maxdepth 1 -type f -print0|xargs -0 your command

謝謝,好¹Õ....